The correct choice is (c) S = \(\frac {G}{(n – 1)}\)
For explanation I would say: In order to increase the range of an ammeter n times, the value of shunt resistance to be connected in parallel is given by:
S = \(\frac {G}{(n – 1)}\)
In order to increase the range of voltmeter n times, the value of resistance to be connected in series with galvanometer is given by:
R = (n – 1) G