Right answer is (a) True
Easy explanation: Yes, this is a true statement. The explanation is given as follows:
E = E0 sinωt.
Erms = \(\frac {E_0}{\sqrt {2}} = \frac {50}{\sqrt {2}}\)
Erms = 35.35 V.
Irms = \(\frac {E_{rms}}{R} \, = \, \frac {35.5}{5} \)
Irms = 7.07 A.
Power dissipated = Ev × Iv = 35.35 × 7.07
Power dissipated = 249.92 W ≈ 250 W.