Question

Calculate the kinetic energy of a photoelectron (in eV) emitted on shining light of wavelength 6.2 × 10^-6 m on a metal surface. The work function of the metal is 0.1 eV.

(a) 10 eV

(b) 0.1 eV

(c) 0.01 eV

(d) 1000 eV

I have been asked this question in my homework.

I'd like to ask this question from Einstein’s Photoelectric Equation : Energy Quantum of Radiation topic in section Dual Nature of Radiation and Matter of Physics – Class 12

Answer 1

Correct option is (b) 0.1 eV

Easy explanation: Kmax = \(( \frac {hc}{\lambda })\) – W0

Kmax = \( [ \frac {(6.6 \times 10^{-34} \times 3 \times 10^8 )}{(6.2 \times 10^{-6} \times 1.6 \times 10^{-19}) }] \) – 0.1.

Kmax = 0.2 – 0.1

Kmax = 0.1 eV