Question

The stopping potential in an experiment on the photoelectric effect is 1.5 V. What is the maximum kinetic energy of the photoelectrons emitted?

(a) 1.5 eV

(b) 3 eV

(c) 4.5 eV

(d) 6 eV

This question was posed to me in final exam.

This question is from Einstein’s Photoelectric Equation : Energy Quantum of Radiation in portion Dual Nature of Radiation and Matter of Physics – Class 12

Answer 1

Correct choice is (a) 1.5 eV

Explanation: Kmax = eV0

Kmax = 1.6 × 10^-19 C × 1.5 V

Kmax = 24 × 10^-19 J

It can also be converted into units of electron volts that will be:

Kmax = 1.5 eV