Right answer is (c) 1^o
The best I can explain: The required equation ➔ δ=(μ-1)A
When two prisms are combined, then:
δ=δ+δ’=(μ-1)A+(μ’-1)A’=0
So, A’=-\(\frac {(\mu-1)A}{\mu^{‘}-1}\)
A’=-\(\frac {(1.15-1)}{1.45-1}\) × 3
A’=-1^o
Therefore, the angle of the other prism is 1^o and opposite of the first prism.