Question

Calculate the dispersive power of crown glass where μV=1.456 and μR=1.414.

(a) 0.0096

(b) 0.45

(c) 0.96

(d) 0.096

I got this question by my college director while I was bunking the class.

I'm obligated to ask this question of Ray Optics in portion Ray Optics and Optical Instruments of Physics – Class 12

Answer 1

The correct answer is (d) 0.096

The best I can explain: Given: The refractive index for violet color = 1.456; Refractive index for red color = 1.414

Required equation ➔

ω=\(\frac {\mu_V – \mu_R}{\mu – 1}\)

Also, μ=\(\frac {(\mu_V+\mu_R)}{2}\)

μ=\(\frac {1.456+1.414}{2}\)=1.435

Thus, ω=\(\frac {1.456-1.414}{1.435-1}\)

ω=\(\frac {0.042}{0.435}\)

ω=0.096

Therefore, the dispersive power of crown glass is 0.096.