Question

What is the de – Broglie wavelength associated with an electron, accelerated through a potential difference of 200 volts?

(a) 1 nm

(b) 0.5 nm

(c) 0.0056 nm

(d) 0.086 nm

I have been asked this question by my college director while I was bunking the class.

I'd like to ask this question from Wave Nature of Matter in chapter Dual Nature of Radiation and Matter of Physics – Class 12

Answer 1

Right choice is (d) 0.086 nm

The explanation is: Given: Potential difference (V) = 200 V

The de – Broglie wavelength is given as:

λ=\(\frac {h}{p} = \frac {h}{mv} = \frac {1.227}{\sqrt {V}}\) nm

λ=\(\frac {1.227}{\sqrt {200}}\)

λ=0.086 nm