The correct answer is (b) 1273\frac{1}{273}2731 of the original volume of the gas.
Explanation:
This question is based on Charles' Law, which states that at constant pressure, the volume of a gas is directly proportional to its temperature (measured in Kelvin).
V∝TorV1T1=V2T2V \propto T \quad \text{or} \quad \frac{V_1}{T_1} = \frac{V_2}{T_2}V∝TorT1V1=T2V2
According to Charles' Law:
- The temperature must be measured in Kelvin.
- If the temperature increases by 1 degree Celsius (which is equivalent to 1 K in terms of temperature change), the volume increases by a fraction of the original volume.
For a gas at a temperature T1T_1T1, an increase in temperature of 1 degree Celsius (1 K) will cause the volume to increase by 1273\frac{1}{273}2731 of the original volume. This is because the volume change per degree is proportional to the initial temperature in Kelvin.
Example:
If the gas is initially at T1=273 KT_1 = 273 \, \text{K}T1=273K, increasing the temperature by 1 K will result in a volume increase of 1273\frac{1}{273}2731 of the original volume.
Thus, the correct option is (b) 1273\frac{1}{273}2731 of the original volume of the gas.