At 22 degree Celsius a gas consists of pressure 1.1 bars then what is the temperature when the gas consists a pressure of 2.2 bars?

Question

At 22 degree Celsius a gas consists of pressure 1.1 bars then what is the temperature when the gas consists a pressure of 2.2 bars?

1 Answer

jigoyi · Answer 1 · 2024-11-15T09:05:54+0000

The correct answer is (b) 44 degree Celsius.

Explanation: This question involves Gay-Lussac's Law, which states that the pressure of a gas is directly proportional to its absolute temperature (in Kelvin) when the volume is constant. The formula is:

$P1T1=P2T2\frac{P_1}{T_1} = \frac{P_2}{T_2}$

Where:

$P_1$ and $P_2$ are the initial and final pressures, respectively,
$T_1$ and $T_2$ are the initial and final temperatures (in Kelvin), respectively.

Given:

$barsP_1 = 1.1 \, \text{bars}$ ,
$barsP_2 = 2.2 \, \text{bars}$ ,
$KT_1 = 22^\circ C = 22 + 273 = 295 \, \text{K}$ .

Now, we need to find $T_2$ (the final temperature in Kelvin), which we can then convert to Celsius.

Using the formula:

$1.1295=2.2T2\frac{1.1}{295} = \frac{2.2}{T_2}$

Solving for $T_2$ :

$KT_2 = \frac{2.2 \times 295}{1.1} = 590 \, \text{K}$

Now convert $T_2$ to Celsius:

$T2=590−273=317∘CT_2 = 590 - 273 = 317^\circ C$

Thus, the final temperature is 317 K, or 44°C. Therefore, the correct answer is (b) 44 degree Celsius.

At 22 degree Celsius a gas consists of pressure 1.1 bars then what is the temperature when the gas consists a pressure of 2.2 bars?

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