Question

Calculate the Gibbs free energy for the conversion of oxygen to Ozone at room temperature if KP is given as 2.47 x 10^-29.

(a) 163 kJ/mol

(b) 163 J/mol

(c) 163 kJ

(d) 163 k/mol

I have been asked this question in class test.

My question comes from Gibbs Energy Change and Equilibrium topic in chapter Thermodynamics of Chemistry – Class 11

Answer 1

The correct choice is (a) 163 kJ/mol

Explanation: The chemical equation for the conversion of oxygen to Ozone is 3/2O2 → O3. We have the equation, ΔG = – 2.303 RT log Kp. So by substituting we get ΔG = – 2.303 x 8.314 J/K-mol x 293K x 2.47 x 10^-29 = 163000 J/mol = 163 kJ/mol.