Question

In the equation, ΔG = – 2.303 RT logK, what is K?

(a) change in temperature

(b) kelvin

(c) equilibrium constant

(d) change in enthalpy

The question was asked during a job interview.

I'm obligated to ask this question of Gibbs Energy Change and Equilibrium in division Thermodynamics of Chemistry – Class 11

Answer 1

Correct choice is (c) equilibrium constant

The best I can explain: In the above equation ΔG = – 2.303 RT logK, G is the change in standard Gibbs free energy, R is the universal gas constant, T is temperature, K is the equilibrium constant while log stands for the logarithm of base 10.