Question

The equilibrium constant for a cell reaction, Cu(g) + 2Ag^+(aq) → Cu^2+(aq) + 2Ag (s) is 4 × 10^16. Find E° (cell)  for the cell reaction.

(a) 0.63 V

(b) 0.49 V

(c) 1.23 V

(d) 3.24 V

This question was addressed to me in my homework.

My doubt is from Electrochemistry in chapter Electrochemistry of Chemistry – Class 12

Answer 1

Right choice is (b) 0.49 V

Explanation: Given, equilibrium constant Kc = 4 × 10^16

E° (cell) = \(\frac{0.059}{2}\)log10 Kc

E°(cell) = \(\frac{0.059}{2}\)log10 (4 × 10^16)=0.49V.