Question

What is the number of electrons transferred in an equation if the Nernst equation is E(cell) = E°(cell) – 9.83 × 10^-3 × log10 (Anode / Cathode)?

(a) 2

(b) 6

(c) 4

(d) 1

I have been asked this question in my homework.

My question is taken from Electrochemistry in division Electrochemistry of Chemistry – Class 12

Answer 1

The correct choice is (b) 6

Explanation: Nernst equation = E°(cell) – \(\frac{0.059}{n}\) log10(Anode / Cathode)

On comparing both the formulae,  \(\frac{0.059}{n}\) = 9.83 × 10^-3

n= 6.