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The rate constant of a reaction is k=3.28 × 10^-4 s^-1. Find the order of the reaction.

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The rate constant of a reaction is k=3.28 × 10^-4 s^-1. Find the order of the reaction.

(a) Zero order

(b) First order

(c) Second order

(d) Third order

I got this question in an interview for internship.

Asked question is from Rate of a Chemical Reaction topic in portion Chemical Kinetics of Chemistry – Class 12

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The correct answer is (b) First order

Best explanation: Given,

 k= 3.28 × 10^-4 s^-1

 The general formula to find the units for rate constant, k=(mol L^-1)^1-ns^-1 where n is the order of the reaction. The value of n must be 1 for (mol L^-1)^1-ns^-1 to become s^-1. Therefore, k=3.28 × 10^-4s^-1 represents a first order reaction.

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