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The rate law for the reaction involved in inversion of cane sugar is R=k [C12H22O11] [H2O].

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in Chemistry – Class 12 by (188k points)
The rate law for the reaction involved in inversion of cane sugar is R=k [C12H22O11] [H2O].

(a) True

(b) False

I got this question in an online interview.

I'd like to ask this question from Rate of a Chemical Reaction topic in section Chemical Kinetics of Chemistry – Class 12

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The correct choice is (b) False

Easy explanation: The reaction for the inversion of cane sugar is C12H22O11 + H2O → glucose + fructose.

In this reaction water is present in excess and belongs to a pseudo first order reaction, even though the molecularity is 2 the order of the reaction is 1 so the rate law R=k[C12H22O11].

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