Question

Bansal has 7 times as many two-rupee coins as he has five-rupee coins. If he has in all a sum of rupees 95, how many coins of each denomination does he have?

(a) 5 two-rupee and 2 five-rupee

(b) 15 two-rupee and 5 five-rupee

(c) 5 two-rupee and 15 five-rupee

(d) 15 two-rupee and 5 five-rupee

The question was posed to me in final exam.

My doubt is from Solving Linear Equations with Variables on Both the Sides in portion Linear Equations in One Variable of Mathematics – Class 8

Answer 1

Correct option is (b) 15 two-rupee and 5 five-rupee

To explain I would say: Let the number of five-rupee coins with Bansal be x. Then the number of two-rupee coins will be 7x. The amount from

(i) Five-rupee coins = 5x

(ii) Two-rupee coins = 2x × 7 = 14x

Hence the total amount with Bansal is 19x.

∴ 19x = 95

∴ x = 5

Thus, the number of five-rupee coin = 5

and number of two-rupees coin = 15.