Question

In a right angle ∆ABC, AB=12, BC=5 and Angle ABC=90°. Find AC.

(a) 169

(b) 13

(c) 17

(d) 14

This question was posed to me in an online interview.

I need to ask this question from Pythagorean Triplet in division Squares and Square Roots of Mathematics – Class 8

Answer 1

The correct option is (b) 13

For explanation: This triangle is a right angled triangle so we can use Pythagoras theorem. Therefore, we get

∴ AC^2 = AB^2 + BC^2

∴ AC^2 = 12^2 + 5^2

∴ AC^2 = 144 + 25

∴ AC^2 = 169

∴ AC = 13.