Using ruler and compass how will you construct ∆ABC, if AB=3.5, BC=6 and angle ABC=60^o?
(a) Draw line BC=6 cm and an angle CBA=600. Cut off AB=3.5. Join AC, triangle ABC is the required triangle
(b) Draw line BC=6 cm and AB= 3.5 and then angle ABC=60o, ABC is the required triangle
(c) Draw line AB= 3.5cm and cut off AB = 6 cm at any point and make angle CBA=600
(d) Draw angle CBA= 600 and make
I got this question in a job interview.
This interesting question is from Loci of Points in chapter Lettering Practice, Scales & Curves of Civil Engineering Drawing