Question

x^2 + 8x + 16 is a multiplier of x+4.

(a) True

(b) False

I have been asked this question during an interview for a job.

This interesting question is from Remainder Theorem topic in chapter Polynomials of Mathematics – Class 9

Answer 1

The correct choice is (a) True

To explain: p(x) is said to be multiplier of x-a if p(a) = 0.

Therefore, checking whether p(-4) is zero of p(x) or not.

p(-4) = (-4)^2 + 8(-4) + 16

= 16 – 32 +16

= 32 – 32

= 0

p(-4) = 0, so we can say that x^2 + 8x + 16 is a multiplier of x+4.

Or in other words, we can say that there we get “0” as a remainder when we divide x^2 + 8x + 16 by x+4.