Correct option is (a) \(\frac {3}{5}\)
The best I can explain: tanθ = \(\frac {BC}{AC} = \frac {3}{4} = \frac {3k}{4k}\)
Hence, BC = 3k, AC = 4k
Using Pythagoras theorem
AB^2 = AC^2 + BC^2
AB^2 = 4k^2 + 3k^2
AB = 5k
sinθ = \(\frac {BC}{AB} = \frac {3k}{5k} = \frac {3}{5}\)