The correct choice is (d) 10 cm
Best explanation: ABCD is a rhombus. The side of the rhombus is 13 cm and the length of one of its diagonal is 24 cm.
Let the length of other diagonal be 2x cm.
Since, diagonals of a rhombus bisect each other. Therefore, AE = x cm and DE = 12 cm
Now, in ∆AED
AD^2 = AE^2 + DE^2
13^2 = x^2 + 12^2 (Since, AD is the altitude of the triangle it will bisect BC)
x^2 = 169 – 144
x^2 = 25
x = √25 = 5 cm
AC = 2 × AE = 2 × 5 = 10 cm