Correct choice is (a) \(\frac {1}{2}\)
Explanation: Total number of outcomes are {1, 2, 3, 4, 5, 6} = 6
Even numbers in total outcomes are {2, 4, 6} = 3
P(E) = \(\frac {Number \, of \, favorable \, outcomes}{Total \, number \, of \, outcomes}\)
= \(\frac {3}{6}\)
= \(\frac {1}{2}\)