Question

If sin x=1/2 and cos x=\(\sqrt{3}\)/2, then find sin 2x.

(a) \(\sqrt{3}\)/2

(b) 1/2

(c) 1/\(\sqrt{2}\)

(d) 1

This question was posed to me in quiz.

The doubt is from Trigonometric Functions of Sum and Difference of Two Angles-2 in portion Trigonometric Functions of Mathematics – Class 11

Answer 1

The correct answer is (a) \(\sqrt{3}\)/2

For explanation: We know, sin2x = 2 sin x cos x

sin 2x = 2*1/2*\(\sqrt{3}\)/2

sin 2x = \(\sqrt{3}\)/2.