Correct choice is (c) (k + 1)^2 (k + 4) k (k + 2)
Easiest explanation: In mathematical induction, if P(k) is true, we need to prove that P(k + 1) is also true. Here P(k + 1) is found by substituting (k + 1) in place of k. P(k + 1) = (k + 1)^2 (k + 1 + 3) ((k + 1)^2 – 1)
P(k + 1) = (k + 1)^2 (k + 4) (k^2 + 1 + 2k – 1)
P(k + 1) = (k + 1)^2 (k + 4) (k^2 + 2k)
P(k + 1) = (k + 1)^2 (k + 4) k (k +2)