The correct option is (b) A≥G
Easiest explanation: We know, A.M. of two numbers a and b is (a + b)/2
Also, G.M. of two numbers a and b is \(\sqrt{ab}\)
A-G = (a + b)/2 – \(\sqrt{ab} = ((a + b) – 2\sqrt{ab})/2 = (\sqrt{a} – \sqrt{b})^2\) / 2 ≥ 0
So, A≥G.