Right choice is (b) \(\frac{8±3\sqrt{7}}{1}\)
Best explanation: We know, G.M. of two numbers a and b is √ab.
So, a + b = 4 √ab
Squaring we get, a^2+b^2 = 16ab
=>(a/b) + (b/a) = 16
Let x = a/b.
So, x + 1/x = 16 => x^2 – 16x + 1 = 0
=>x = \(\frac{16±\sqrt{256-4}}{2} = \frac{16±\sqrt{252}}{2} = \frac{16±6\sqrt{7}}{2} = \frac{8±3\sqrt{7}}{1}\).