Right choice is (c) [10/3, ∞)
To explain: We have, (2x^2 – 2x – 3) / (x^2 + x + 1) ≤ a ᵾ x € R
=> 2x^2 – 2x – 3 ≤ a(x^2 + x + 1) ᵾ x € R
=> (2 – a)x^2 – (2 – a)x – (3 – a) ᵾ x € R
2 – a < 0 and (2 – a)x^2 – 4(2 – a)(3 – a) ≤ 0 ᵾ x € R
So, a > 2 and a ≤ 2 or a ≥ 10/3
=> a ≥ 10/3
Therefore, a € [10/3, ∞)