Right option is (c) a & b=ab – 8
The explanation: The binary operation ‘&’ is commutative but not associative for a*b=ab-8.
For Commutative: a & b=ab-8 and b & a=ba-8
ab-8=ba-8. Hence, a & b=ab-8 is commutative.
For Associative: (a &b)& c=(ab-8)& c=(ab-8)c-8=abc-8c-8=abc-8c-8.
a& (b &c)=a&(bc-8)=a(bc-8)-8=abc-8a-8.
⇒(a&b) & c≠a& (b& c). Hence, the function is not associative.