Correct choice is (b) \(\begin{bmatrix}20&8\\-4&2\\12&-4\end{bmatrix}\)
The best I can explain: Given matrix A=\(\begin{bmatrix}5&8\\-1&2\\3&-4\end{bmatrix}\)
Applying the column operation, C1→4C1 we get
\(\begin{bmatrix}4(5)&8\\4(-1)&2\\4(3)&-4\end{bmatrix}\)=\(\begin{bmatrix}20&8\\-4&2\\12&-4\end{bmatrix}\)