Correct option is (a) 5.0267
For explanation: Let y=(x)^1/3. Let x=125 and Δx=2
Then, Δy=(x+Δx)^1/3-x^1/3
Δy=(127)^1/3-(125)^1/3
(127)^1/3=Δy+5
dy is approximately equal to Δy is equal to
dy=\(\frac{dy}{dx}\)Δx
dy=\(\frac{1}{3x^{2/3}}\).Δx
dy=\(\frac{1}{3×125^{2/3}} (2)\)
dy=2/75=0.0267
∴ The approximate value of (127)^1/3 is 5+0.0267=5.0267