Right answer is (a) 3.34
The best I can explain: Let y=\(\sqrt{x}\). Let x=9 and Δx=2
Then, Δy=\(\sqrt{x+Δx}-\sqrt{x}\)
Δy=\(\sqrt{11}-\sqrt{9}\)
\(\sqrt{11}\)=Δy+3
dy is approximately equal to Δy is equal to
dy=\(\frac{dy}{dx}\)Δx
dy=\(\frac{1}{(2\sqrt{x})}\).Δx
dy=\(\frac{1}{(2\sqrt{9})}(2)\)
dy=2/6=0.34
∴ The approximate value of \(\sqrt{11}\) is 3+0.34=3.34.