Right option is (a) 2x/(x^2 + 4) dx
For explanation I would say: Let, y = f(x) = log(x^2 + 4)
So f(x) = log(x^2 + 4)
On differentiating it we get,
f’(x) = d/dx[log(x^2 + 4)]
So f’(x) = 2x/(x^2 + 4)
So the differential equation is:
dy = f’(x)dx
Hence, dy = 2x/(x^2 + 4) dx