Right choice is (c) 12
To explain I would say: Here, in L.H.S we have,
\(\begin{vmatrix}2 & 5 & 8 \\1 & 4 & 7 \\6 & 4 & \alpha \end {vmatrix}\)
So, for trivial roots the above value is = 0
=>\(\begin{vmatrix}2 & 5 & 8 \\1 & 4 & 7 \\6 & 4 & \alpha \end {vmatrix}\) = 0
Solving it further we get α = 12