The correct answer is (b) B = \(\begin{bmatrix}4&2\\4&1\end{bmatrix}\)
Best explanation: Given that, A+B = \(\begin{bmatrix}6&7\\5&0\end{bmatrix}\)and A = \(\begin{bmatrix}2&5\\1&-1\end{bmatrix}\)
⇒B=(A+B)-A = \(\begin{bmatrix}6&7\\5&0\end{bmatrix}\)–\(\begin{bmatrix}2&5\\1&-1\end{bmatrix}\)
B = \(\begin{bmatrix}4&2\\4&1\end{bmatrix}\)