The correct answer is (b) B = \begin{bmatrix}4&2\\4&1\end{bmatrix}
Best explanation: Given that, A+B = \begin{bmatrix}6&7\\5&0\end{bmatrix}and A = \begin{bmatrix}2&5\\1&-1\end{bmatrix}
⇒B=(A+B)-A = \begin{bmatrix}6&7\\5&0\end{bmatrix}–\begin{bmatrix}2&5\\1&-1\end{bmatrix}
B = \begin{bmatrix}4&2\\4&1\end{bmatrix}