Question

Find the transpose of A=\(\begin{bmatrix}1&-2\\-1&5\end{bmatrix}\).

(a) A=\(\begin{bmatrix}-1&-2\\-1&-5\end{bmatrix}\)

(b) A=\(\begin{bmatrix}1&2\\1&5\end{bmatrix}\)

(c) A=\(\begin{bmatrix}-1&2\\-1&5\end{bmatrix}\)

(d) A=\(\begin{bmatrix}1&-1\\-2&5\end{bmatrix}\)

I have been asked this question during a job interview.

My question comes from Transpose of a Matrix in division Matrices of Mathematics – Class 12

Answer 1

Correct option is (d) A=\(\begin{bmatrix}1&-1\\-2&5\end{bmatrix}\)

The explanation: A=\(\begin{bmatrix}1&-2\\-1&5\end{bmatrix}\). To find the transpose of the matrix, interchange the rows with columns and columns with rows.

Hence, A’=\(\begin{bmatrix}1&-1\\-2&5\end{bmatrix}\).