The correct answer is (d) 3 sq.units
The explanation is: The area of the triangle (0,2), (0, 0), (3, 0) with vertices is given by
Δ=\(\frac{1}{2}\begin{Vmatrix}0&2&1\\0&0&1\\3&0&1\end{Vmatrix}\)
Expanding along R3, we get
Δ=\(\frac{1}{2}\) {0-0+3(2-0)}
Δ=3 sq.units.