Question

Value after differentiating cos (sinx) is _________

(a) sin (sinx).cosx

(b) -sin (sinx).cosx

(c) sin (sinx)

(d) sin (cosx).cosx

I have been asked this question in a job interview.

The doubt is from Differentiability in section Continuity and Differentiability of Mathematics – Class 12

Answer 1

The correct option is (b) -sin (sinx).cosx

The best I can explain: We differentiate the given function with the help of chain rule so we first differentiate the outer function which becomes –sin and then we differentiate the inner function sinx which is differentiated and comes out to be cosx, hence the differentiated function comes out to be -sin (sinx).cosx.