Question

Find \(\frac{dy}{dx}\) of 2x+3y = sinx.

(a) \(\frac{cosx-2}{3}\)

(b) \(\frac{cosx-2}{2}\)

(c) \(\frac{cosx-3}{2}\)

(d) \(\frac{sinx-2}{3}\)

This question was addressed to me in an interview for internship.

The query is from Differentiability in portion Continuity and Differentiability of Mathematics – Class 12

Answer 1

The correct answer is (a) \(\frac{cosx-2}{3}\)

Easiest explanation: Differentiating on both sides we get 2 + 3\(\frac{dy}{dx}\) = cosx.

3\(\frac{dy}{dx}\) = cosx-2.

\(\frac{dy}{dx} = \frac{cosx-2}{3}\).