Correct choice is (c) [(2 + √3)/2√3 * (log (√3(y + 2) – (x – 1))) – (2 – √3)/2√3 * (log (√3(y + 2) – (x – 1)))]
Best explanation: Put x = X + h, Y = Y + k,
We have, dY/dX = (X + 2Y +(h + 2k + 3))/ 2X + 3Y + (2h + 3k + 4)
So, (a – b)x = (a – b)
To determine h and k we set,
2h + 3k + 4 = 0 and h + 2k + 3 = 0
=> h = 1 and k = – 2
Therefore, dY/dX = (X + 2Y) / (2X + 3Y)
Putting Y = VX, we get,
V + X dV/dX = (1 + 2V)/(2 + 3V)
= (1 + 2V)/(3V^2 – 1)*dV = -dX/X
=> [(2 + √3)/(2(√3V – 1)) – (2 – √3)/(2(√3V – 1))] dV = -dX/X
Simplifying it further, we get;
[(2 + √3)/2√3 * (log (√3Y – X)) – (2 – √3)/2√3 * (log (√3Y – X))]
Where, X = x – 1 and Y = y + 2