The correct option is (a) The above statement is valid
For explanation: Let a particle be moving along the straight-line OX and P be its position at time t, when OP = x. Clearly, the velocity and acceleration of the particle at P are dx/dt and d^2x/dt^2 respectively.
If possible, let us assume,
dx/dt α x
dx/dt = kx, where k is a constant variation.
Now, d^2x/dt^2 = d(kx)/dt = k(dx/dt)
= k^2x
At the starting point O, we have x = 0 and we see that dx/dt = 0 and d^2x/dt^2 = 0, when x = 0 that is, both velocity and acceleration of the particle are zero at x = 0 and the particle remains at rest at O.
Therefore, it is impossible for a particle to have any motion under the given condition.