Question

Which of these is the vibrational rate equation?

(a) \(\frac {de_{vib}}{dt} = \frac {1}{τ}\)(e\(_{vib}^{eq}\) – evib)

(b) τ = \(\frac {1}{k_{1, 0} (1 – e^{- hv/kT} )}\)

(c) evib = τ(e\(_{vib}^{eq}\) – evib)

(d) \(\frac {de_{vib}}{dt}\) = \(\frac {1}{τ}\)(e\(_{vib}^{eq}\) – evib)

I had been asked this question in an online quiz.

This intriguing question originated from Vibrational Rate Equations in division Properties of High Temperature Gases of Aerodynamics

Answer 1

Correct choice is (a) \(\frac {de_{vib}}{dt} = \frac {1}{τ}\)(e\(_{vib}^{eq}\) – evib)

Best explanation: The vibrational rate equation gives a relation between evib which is the time rate change with the difference between the equilibrium and the local instantaneous non – equilibrium value (e\(_{vib}^{eq}\) – evib). It is given by the following relation which is a differential equation:

\(\frac {de_{vib}}{dt} = \frac {1}{τ}\)(e\(_{vib}^{eq}\) – evib)