Right option is (a) 1.80m/s
The explanation: Given, lift coefficient = 2.8, q=10Pa, n=5
Since density is not given we will take as sea level.
Load factor n = q*CL/(W/S)
(W/S)/CL = q/n = 10/5 = 2.
Now, stall speed V is given by,
V = \(\sqrt{2*(\frac{W}{S})/(\rho*CL)}\)
= \(\sqrt{2*2/1.225}\) = 1.80m/s.