Right answer is (b) False
The best I can explain: The endurance of cruise method 3 is not identical to that of cruise method 1. E=\(\Big[\frac{E_{max}}{C}\Big]2\Big\{tan^{-1}\Big[\frac{1}{u_{i}^2}\Big]-tan^{-1}\Big[\frac{1}{\omega u_{i}^2}\Big]\Big\}\)where where V is true airspeed, C is specific fuel consumption, Emax is endurance, u is relative airspeed and ω is fuel ratio.