Question

What is the range of the power producing engine?

(a) RP=\(\big[\frac{\eta}{C_P}E_{max}\big]\big\{\frac{2u^2}{u^4+1}\big\}\)lnω

(b) RP=\(\big[\frac{\eta}{C_P}E_{max}\big]\big\{\frac{2u^3}{u^4+1}\big\}\)lnω

(c) RP=\(\big[\frac{\eta}{C_P}\big]\big\{\frac{2u^2}{u^4+1}\big\}\)lnω

(d) RP=\(\big[\frac{V_{mdi}}{C_P}E_{max}\big]\big\{\frac{2u^3}{u^4+1}\big\}\)lnω

I had been asked this question during an interview for a job.

The origin of the question is Cruising Performance topic in portion Cruising Performance of Aircraft Performance

Answer 1

Right option is (a) RP=\(\big[\frac{\eta}{C_P}E_{max}\big]\big\{\frac{2u^2}{u^4+1}\big\}\)lnω

The best explanation: The correct equation for range of thrust producing engine is given by the equation RP=\(\big[\frac{\eta}{C_P}E_{max}\big]\big\{\frac{2u^2}{u^4+1}\big\}\)lnω where V is true airspeed, C is specific fuel consumption, Emax is endurance, η is propeller efficiency and ω is fuel ratio.