Question

Which of the following is the correct formula of airborne distance with respect to aircraft weight?

(a) SA=\(\frac{W}{(F_N-D)_{av}}\Big\{\frac{V_{2}^2+V_{LOF}^2}{2g}+35\Big\}\)

(b) SA=\(\frac{W}{(F_N+D)_{av}}\Big\{\frac{V_{2}^2+V_{LOF}^2}{2g}+35\Big\}\)

(c) SA=\(\frac{W}{(F_N+D)_{av}}\Big\{\frac{V_{2}^2-V_{LOF}^2}{2g}+35\Big\}\)

(d) SA=\(\frac{W}{(F_N-D)_{av}}\Big\{\frac{V_{2}^2-V_{LOF}^2}{2g}+35\Big\}\)

This question was addressed to me in my homework.

The above asked question is from Effect on the Take-off Distances of Flight Variables in portion Take-off and Landing Performance of Aircraft Performance

Answer 1

Correct option is (d) SA=\(\frac{W}{(F_N-D)_{av}}\Big\{\frac{V_{2}^2-V_{LOF}^2}{2g}+35\Big\}\)

To elaborate: The airborne distance is given by SA=\(\frac{W}{(F_N-D)_{av}}\Big\{\frac{V_{2}^2-V_{LOF}^2}{2g}+35\Big\}\) where

W is weight

D is drag

G is acceleration due to gravity

V is velocity

FN is normal force.