Question

The effect of TAS on airborne distance is half that of the ideal case.

(a) True

(b) False

I have been asked this question during an online exam.

This is a very interesting question from Effect on the Take-off Distances of Flight Variables topic in section Take-off and Landing Performance of Aircraft Performance

Answer 1

Correct answer is (a) True

The explanation: The effect of TAS on airborne distance is half that of the ideal case. The airborne distance is given by SA=\(\frac{W}{(F_N-D)_{av}}\Big\{\frac{V_{2}^2-V_{LOF}^2}{2g}+35\Big\}\) where W is weight

D is drag

G is acceleration due to gravity

V is velocity

FN is normal force.