The correct choice is (a) cos^-1 (±n)
Best explanation: The nulls of the N- element array is given by
\(θ_n=cos^{-1}(\frac{λ}{2πd} \left[-β±\frac{2πn}{N}\right])=cos^{-1}(\frac{λ}{2πd} \left[±\frac{2πn}{N}\right])\)
⇨ \(θ_n=cos^{-1}(\frac{λ}{2π(λ/4)}\left[±\frac{2πn}{N}\right])=cos^{-1} (±\frac{4n}{4})=cos^{-1} (±n) \left[n=1,2,3 \,and \,n≠N,2N…\right]\)