Right answer is (a) 60
To explain: The nulls of the N- element array is given by \(θ_n=cos^{-1}(\frac{λ}{2πd} [-β±\frac{2πn}{N}])\)
Since its given broad side array \(β=±kd=±\frac{2πd}{λ}=±\frac{π}{2},\)
\(θ_n=cos^{-1}(\frac{2}{π} [∓\frac{π}{2}±\frac{2πn}{8}])\)
\(=cos^{-1}([∓1±\frac{n}{2}])\)
First null at n=1; \(θ_n= =cos^{-1}([1±\frac{1}{2}]) (considering \,β=-\frac{π}{2}) \)
\(θ_n =cos^{-1} (\frac{1}{2})\,or \,cos^{-1} (3/2) \)
\(θ_n =cos^{-1} (\frac{1}{2})=60.\)