Correct answer is (b) \(cos^{-1} (±\frac{n}{2})\)
Best explanation: The nulls of the N- element array is given by
\(θ_n=cos^{-1}(\frac{λ}{2πd}\left[-β±\frac{2πn}{N}\right])=cos^{-1}(\frac{λ}{2πd} [±\frac{2πn}{N}])\)
⇨ \(θ_n=cos^{-1}(\frac{λ}{2π(λ/4)}) [±\frac{2πn}{N}])=cos^{-1} (±\frac{4n}{8})=cos^{-1} (±\frac{n}{2}) [n=1,2,3 \,and\, n≠N,2N…]\)