Question

A container has H2 at 27^oC and molar volume 1 liter/mole, if a = 9.24 atm(liter/mole), b = 0.0907 liter/mole, what is the temperature of H2? (Use vander waal equation)

(a) 7.5 atm

(b) 12.4 atm

(c) 15.6 atm

(d) 17.8 atm

The question was asked by my school teacher while I was bunking the class.

My question is based upon Equations of State in section Real Gases: Equations of State, Single Component Two Phase Systems, Saturation & Condensation of Basic Chemical Engineering

Answer 1

Correct option is (d) 17.8 atm

Easiest explanation: (p + a/V^2)(V – b) = RT, => p = 0.0821*300/(1 – 0.0907) – 9.24/1^2 = 17.8 atm.